Perimeter of the shaded region =Perimeter of APB
+ Perimeter of BSD
+ Perimeter of DQC
+ Perimeter of CRA
Now given that APB and DQC are a semicircle of radius 7/2 cm.
Perimeter of a semicircle= π r
As the radius of the semicircles is equal, their perimeters will also be equal.
Perimeter of APB= Perimeter of DQC = π r =
Radius of BSD=Radius of CRA=7cm
Perimeter of BSD = Perimeter of CRA = π R =
Total perimeter of shaded region= 11 + 22 + 11 + 22 =66cm
Circumference of circle = 2πr
2πr = 44cm(given)
Area of quadrant = πr2/4
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The cost of fenciRS Aggarwal - Mathematics