Q. 114.4( 10 Votes )

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Answer :

Perimeter of the shaded region =Perimeter of APB

+ Perimeter of BSD


+ Perimeter of DQC


+ Perimeter of CRA


Now given that APB and DQC are a semicircle of radius 7/2 cm.


Perimeter of a semicircle= π r


As the radius of the semicircles is equal, their perimeters will also be equal.


Perimeter of APB= Perimeter of DQC = π r =


Similarly,


Radius of BSD=Radius of CRA=7cm
Perimeter of BSD = Perimeter of CRA =
π R =


Total perimeter of shaded region= 11 + 22 + 11 + 22 =66cm


Or


Circumference of circle = 2πr


2πr = 44cm(given)



r =


Area of quadrant = πr2/4


=cm2


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