Q. 114.4( 10 Votes )

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Answer :

Perimeter of the shaded region =Perimeter of APB

+ Perimeter of BSD

+ Perimeter of DQC

+ Perimeter of CRA

Now given that APB and DQC are a semicircle of radius 7/2 cm.

Perimeter of a semicircle= π r

As the radius of the semicircles is equal, their perimeters will also be equal.

Perimeter of APB= Perimeter of DQC = π r =


Radius of BSD=Radius of CRA=7cm
Perimeter of BSD = Perimeter of CRA =
π R =

Total perimeter of shaded region= 11 + 22 + 11 + 22 =66cm


Circumference of circle = 2πr

2πr = 44cm(given)

r =

Area of quadrant = πr2/4


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