Q. 115.0( 1 Vote )

In fig. 2, PA and

Answer :

ΔAPB is an isosceles triangle

PAB = PBA


APB + PAB + PBA = 180°


50° + PAB × 2 = 180


PAB = 65°


OAB = 90°


Thus, OAB = OAP - PAB = 90° - 65° = 25°


OR


POR = 120°


reflex POR = 240


PRQ = 1\2 reflex POR = 120


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