# In a Δ ABC, If ∠A = 60°, ∠B =80° and the bisectors of ∠B and ∠C meet at O, then ∠BOC=A. 60°B. 120°C. 150°D. 30°

In

A + B + C = 180o

60o + B + C = 180o

B + C = 120o

B + C = 60o (i)

BOC + OBC + OCB = 180o

BOC + B + C = 180o

BOC + (B + C) = 180o

BOC + 60o = 180o [From (i)]

BOC = 120o

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