Q. 114.5( 11 Votes )

I have drawn an isosceles triangle ABC whose included angle of two equal sides is ABC=45°; the bisector of ABC intersects the side AC at the point D let us determine the circular values of ABD, BAD, CBD and BCD.

Answer :


ABC = 45°




BD is the angle bisector of ABC



BAD + ABC+ BCD = π


ABC is an isosceles triangle


BAD = BCD = x






Rate this question :

How useful is this solution?
We strive to provide quality solutions. Please rate us to serve you better.
Related Videos
Basic Concept of Trigonometry43 mins
Application of Trigonometry45 mins
Fundas of Trigonometry50 mins
Champ Quiz | Trigger on Trigonometry47 mins
Trick to learn all Trigonometric Formulae28 mins
NCERT | Trigonometric Identities52 mins
Concept of Quadratic equation47 mins
Champ Quiz | Trigonometry Important Questions33 mins
Solving NCERT Questions on Trigonometric Identities56 mins
Champ Quiz | NTSE Trigonometry50 mins
Try our Mini CourseMaster Important Topics in 7 DaysLearn from IITians, NITians, Doctors & Academic Experts
Dedicated counsellor for each student
24X7 Doubt Resolution
Daily Report Card
Detailed Performance Evaluation
view all courses
RELATED QUESTIONS :

radian equals to

West Bengal Board - Mathematics