Q. 114.5( 11 Votes )

I have drawn an isosceles triangle ABC whose included angle of two equal sides is ABC=45°; the bisector of ABC intersects the side AC at the point D let us determine the circular values of ABD, BAD, CBD and BCD.

Answer :

ABC = 45°

BD is the angle bisector of ABC

BAD + ABC+ BCD = π

ABC is an isosceles triangle

BAD = BCD = x

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radian equals to

West Bengal Board - Mathematics