Given that two nu

When two dice are thrown, there are 36 possibilities.

However, we are given, every time both dice contain different numbers means doublet is not a possibility.

As, number of doublets are 6, so, sample space, S = 36 – 6 = 30

Number of possibilities of the event when sum of dice is 6, (1, 5), (2, 4), (4, 2), (5, 1)

Here, we won’t take (3, 3) as both dice contain different numbers. So,

⇒ E = 4

So,