Answer :

Given: points A(3, 2, 2) and B(5, 5, 4)


To find coordinates of a point on x-axis which is equidistant from given points.


Formula used:


The distance between any two points (a, b, c) and (m, n, o) is given by,



As, y and z coordinate on x-axis are zero


Let point D any point on x-axis be (x, 0, 0)


AD = BD


Distance between B(5, 5, 4) and D(x, 0, 0) is BD,






Distance between A(3, 2, 2) and D(x, 0, 0) is BD,






As, AD = BD


AD2 = BD2


8 + (3 – x)2 = 41 + (5 – x)2


8 + 9 + x2 – 6x= 41 + 25 + x2 – 10x


17 – 6x = 66 – 10x


10x – 6x = 66 - 17


4x = 49



Hence, coordinates of point D are


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