Q. 114.5( 8 Votes )

Find the equation

Answer :

Let the required equation of circle be


x2 + y2 + 2gx + 2fy + c = 0 ….. (1)


As circle passes through (0,0),(-2,0)(0,3)


Putting (0,0) in (1) to get,


0+0+0+0+c = 0


c= 0


Thus (1) becomes,


x2 + y2 + 2gx + 2fy = 0 ….. (2)


Putting (-2,0) in (2) to get,


(-2)2 + 02 – 4g + 0 = 0


4g = 4


g = 1


Putting (0,3) in (2) to get,


0 + 32 + 0 + 6f = 0


9 + 6f = 0


6f = -9


f = -3/2


Putting g = 1, f=-3/2 in (2) we get,


x2 + y2 + 2x – 3y= 0


Rate this question :

How useful is this solution?
We strive to provide quality solutions. Please rate us to serve you better.
Try our Mini CourseMaster Important Topics in 7 DaysLearn from IITians, NITians, Doctors & Academic Experts
Dedicated counsellor for each student
24X7 Doubt Resolution
Daily Report Card
Detailed Performance Evaluation
caricature
view all courses
RELATED QUESTIONS :

Show that the quaRS Aggarwal - Mathematics

If ( - 1, 3) and RS Aggarwal - Mathematics

Find the equationRS Aggarwal - Mathematics

Find the equationRS Aggarwal - Mathematics

Show that the equRS Aggarwal - Mathematics

Show that the equRS Aggarwal - Mathematics