Q. 115.0( 3 Votes )

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Answer :

Steps of construction:

1. Draw a circle of radius 4 cm. Draw a point B, 6cm away from the centre.

2. Join AB. Make perpendicular bisector of AB and let O be the midpoint.

3. Taking O as centre and OA as radius draw a circle.

Let it intersect at C and D. Join BC and BD.

BC and BD are two tangents.


We need to prove BC and BD are the tangents to the circle.

Join AC and AD.

As BCA is an angle in the semi-circle of the bigger circle.

Angle in a semi-circle is of 90°.

BCA = 90°


Since AC is a radius.

So BC is the tangent as tangent is perependicular to radius.

Similarly BD is tangent.

Hence construction is justifided.

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