Q. 105.0( 2 Votes )

(x+1) is a factor of xn+1 only if
A. n is an odd integer

B. n is an even integer

C. n is a negative integer

D. n is a positive integer

Answer :

Let f (x) = xⁿ +1

Since, x+ 1 is a factor of f (x), so


f (-1) = 9


Thus, n is an odd integer.

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