# Write the number of ways in which 5 boys and 3 girls can be seated in a row so that each girl is between 2 boys.

5 boys can be seated in 5! ways to sit in a row. Now, we can place 3 girls in 4 empty seats between them so that each girl is between 2 boys, and this can be done in 4P3 = 24 ways.

As, the operations are dependent, so, the number of ways in which 5 boys and 3 girls can be seated in a row so that each girl is between 2 boys

= 2880.

The discussion can be shown pictorially as:

[X = 4 empty seats between 2 boys(B)]

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