The plane is given as, .
We can write the equation of the plane in general form as,
2x - y + 2z - 12=0 …………… (1)
Now, to get the normal form of a plane given in general form as, Ax + By + Cz + D=0 where …… (2), we have to divide the equation (1) by , where is the normal vector given as,
Comparing equation (1) with equation (2), we get, D= - 12
So, the distance between the plane and the origin (using formula)
The distance between the plane and the origin is 4 units.
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