Answer :

Let the initial position of plain be P and after landing it position be R.

Now,

Angle of depression while landing, ∠CPR = 20°

Also, ∠ CPR = ∠PRQ (say θ) = 20° [Alternate Angles]

Now,

Speed of plane = 200 km / hr

Time taken for landing = 54 seconds

Distance travelled in landing = PR

Also, distance = speed × time

Now, In ∆PQR

⇒ PQ = 3000 × sin 20°

⇒ PQ = 3000(0.342)

⇒ PQ = 1026 m

So, Plane was at a height of 1026 m at the start of landing.

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