Q. 105.0( 1 Vote )

the foci of the hyperbola 9x2 – 16y2 = 144 are
A. (± 4, 0)

B. (0, ± 4)

C. (± 5, 0)

D. (0, ± 5)

Answer :

Given: 9x2 – 16y2 = 144


To find: coordinates of the foci f(m,n)


9x2 – 16y2 = 144





Formula used:


For hyperbola


Eccentricity(e) is given by,



Foci is given by (±ae, 0)


Here, a = 4 and b = 3





c = 5


Therefore,




Foci: (±5, 0)

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