Q. 105.0( 1 Vote )

# the foci of the hyperbola 9x^{2} – 16y^{2} = 144 are

A. (± 4, 0)

B. (0, ± 4)

C. (± 5, 0)

D. (0, ± 5)

Answer :

**Given:** 9x^{2} – 16y^{2} = 144

**To find:** coordinates of the foci f(m,n)

9x^{2} – 16y^{2} = 144

**Formula used:**

For hyperbola

Eccentricity(e) is given by,

Foci is given by (±ae, 0)

Here, a = 4 and b = 3

⇒ c = 5

Therefore,

Foci: (±5, 0)

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