Q. 105.0( 3 Votes )

The diagonals of a rhombus, ABCD intersect at the point O. If BDC = 50°, then OAB = ?


A. 50o

B. 40o

C. 25o

D. 20o

Answer :

BDC = ABD (Alternate interior angles)

ABD = 50o


Now, In ∆AOB,


DBA = 50o and AOB = 90o


Thus, OAB = 180o − (90o + 50o)


OAB = 180° - 140°


OAB = 40o


Option B is correct.

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