# The diagonals of a rhombus, ABCD intersect at the point O. If ∠BDC = 50°, then ∠OAB = ?A. 50oB. 40oC. 25oD. 20o

BDC = ABD (Alternate interior angles)

ABD = 50o

Now, In ∆AOB,

DBA = 50o and AOB = 90o

Thus, OAB = 180o − (90o + 50o)

OAB = 180° - 140°

OAB = 40o

Option B is correct.

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