Q. 105.0( 1 Vote )

# Prove the following identities:(CBSE 2012)

Applying, C2C2 – 2C1 – 2C3, we get,

Taking, – (a2 + b2 + c2) common from C2 we get,

Applying R2R2 – R1 and R3R3 – R1, we get

= – (a2 + b2 + c2)(a – b)(c – a)[( – (b + a))( – b) – (c)(c + a)]

= (a – b)(b – c)(c – a)(a + b + c)(a2 + b2 + c2)

= R.H.S

Hence, proved.

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