Q. 105.0( 3 Votes )

P is any a point on diagonal BD of parallelogram ABCD. Let’s prove that triangle APD = triangle CPD.

Answer :

Given.


P is any a point on diagonal BD of parallelogram ABCD


Formula used.


Area of triangle = × Base × Height



In triangle APD and triangle CPD


As ABCD is a parallelogram


And BD is the diagonal


it divides both congruent triangles


Hence perpendicular of both the triangles are same


AX= CY


For any place of P on BD


The perpendicular of triangle will be same of as of triangle ADB and triangle CBD


Area of triangle APD = × AX × DP


Area of triangle CPD = × CY × DP


= × AX × DP


Area of triangle APD = Area of triangle CPD


triangle APD = triangle APD


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