Let us write by calculating the area of regular hexagon field of which length of sides is 8 cm. [Hints: If we draw diagonals we get equal six equilateral triangles]

Area of field in the shape of parallelogram ABCD is 96 sq. cm., length of diagonal BD is 12 cm. What is the perpendicular length drawn on diagonal BD from the point A?

Let us see the following pictures and calculate the area of its coloured part.

The base of a parallelogram is twice its height. If the area of shape of parallelogram is 98 sq.cm, then let us calculate the length and height of parallelogram.

If perimeter of a rhombus is 440 meter and distance between two parallel sides are 22 meter, let us write by calculating the area of shape of rhombus.

The area of field shaped in trapezium is 1400 sq. dcm. If the perpendicular distance between two parallel sides are 20 dcm and the length of two parallel sides are in the ratio 3 : 4, then let us write by calculating the lengths of two sides.

In a quadrilateral ABCD, AB = 5 meter, BC = 12 meter, CD = 14 meter, DA = 15 meter and ∠ABC = 90°, let us write by calculating the area of quadrilateral shape of field.

In parallelogram ABCD, AB = 4 cm., BC = 6 cm. and ∠ABC = 30°, find the area of field in the shape of parallelogram ABCD.

The length of adjacent two sides are 15 cm. and 12 cm. of a parallelogram distance between two smaller sides is 7.5 cm. Then let us calculate the distance between the longer two sides.

The length of one diagonal of rhombus is three times of another diagonal. If the area of field in the shape of rhombus is 96 cm², then the length of long diagonal is

If the length of perpendicular from the intersecting point between two diagonals on any side of square is 2√2 cm, then what is the length of each diagonal of square?