# In the given figu

Observe in ∆BED & ∆ACB, we have

BED = ACB = 90°

Now according to what’s given, DB BC and AC BC we can write,

B + C = 180°

This clearly means BD CA

EBD = CAB [They are alternate angles]

Thus, by AA-similarity theorem, ∆BED ∆ACB

So,

Hence, proved.

Rate this question :

How useful is this solution?
We strive to provide quality solutions. Please rate us to serve you better.
Related Videos
Quiz- Test what you Know45 mins
Quiz- Test what you Know Part 245 mins
Similarity - Apply it like a Champ45 mins
BPT ke Master Kaise Bane?46 mins
Pythagoras Theorem ki Application46 mins
Try our Mini CourseMaster Important Topics in 7 DaysLearn from IITians, NITians, Doctors & Academic Experts
Dedicated counsellor for each student
24X7 Doubt Resolution
Daily Report Card
Detailed Performance Evaluation
view all courses
RELATED QUESTIONS :

In Fig. 4.243, thRD Sharma - Mathematics

In Fig. 4.246, ifRD Sharma - Mathematics

In Fig. 4.244, ifRD Sharma - Mathematics

If <img widRD Sharma - Mathematics

If <img widRD Sharma - Mathematics

If in <img RD Sharma - Mathematics

In a <img wRD Sharma - Mathematics

If <img widRD Sharma - Mathematics

In <img widRD Sharma - Mathematics