Q. 105.0( 10 Votes )

In the given figu

Answer :



As AB is tangent to the circle at point B.


OB AB


[Tangents drawn at a point on circle is perpendicular to the radius through point of contact]


In right angled triangle AOB,


By Pythagoras Theorem,


[i.e. (Hypotenuse)2 = (Base)2 + (Perpendicular)2 ]


(OA)2 = (OB)2 + (AB)2


(17)2 = (8)2 + (AB)2


[As OA = 17 cm is given and OB is radius]


289 = 64 + (AB)2


(AB)2 = 225


AB = 15 cm


Now, AB = AC [Tangents drawn from an external point are equal]


AC = 15 cm

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