Q. 105.0( 3 Votes )

In Fig. 3, AP and

Answer :

It is given in the question that,

APB = 60o


We know that, tangents drawn from an external point of a circle are equal


PA = PB


Also, we know that angles opposite to equal sides are equal


∴∠ PAB = PBA (i)


Sum of angles of a triangle = 180o


In triangle PAB, PAB + PBA + APB = 180o


PAB + PAB + 60o = 180o


2 PAB = 120o


PAB = 60o



Hence, the sides AB and AP are equal to each other i.e. AB = AP = 5 cm


Rate this question :

How useful is this solution?
We strive to provide quality solutions. Please rate us to serve you better.
Try our Mini CourseMaster Important Topics in 7 DaysLearn from IITians, NITians, Doctors & Academic Experts
Dedicated counsellor for each student
24X7 Doubt Resolution
Daily Report Card
Detailed Performance Evaluation
caricature
view all courses