Q. 10

# In ΔABC I have drawn two perpendiculars from two vertices B and C on AC and AB (AC>AB) which are intersected each other at the point P. Let us prove that, AC2 + BP2 = AB2 + CP2

Given: In ΔABC, AC>AB

CE AB

BD AC To prove: AC2 + BP2 = AB2 + CP2

Proof:

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