Q. 105.0( 2 Votes )

# In a trapezium AB

Answer :

Given: AB CD

AB = 2CD ……….(i)

ar (∆ AOB) = 84 cm2

To find: ar (∆ COD) In ∆ AOB and ∆ COD,

AOB = COD [Vertically Opposite angles]

OAB = OCD [Alternate interior angles (AB CD)]

OBA = ODC [Alternate interior angles (AB CD)]

∆ AOB ∆ COD [By AAA criterion]

Now,

The ratios of the areas of two similar triangles are equal to the ratio of squares of any two corresponding sides.

We have Also, from (i), we have  Rate this question :

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