Answer :

x - y = 3


y = x-3 …Equation (i)


xy = 10


Putting the value of y from above Equation (i) we get


x(x-3) = 10


x2-3x = 10


x2-3x-10 = 0


Solving the above equation by the method of factorization we get


x2-5x + 2x + 10 = 0


x(x-5) + 2(x-5) = 0


(x + 2)(x-5) = 0


x = -2,5


Neglecting the negative value


When x = 5, y = 2


x2 + y = 27


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