Q. 103.8( 11 Votes )

Factorise
(i) 6ab - b2 + 12ac - 2bc
(ii) x2 + y - xy - x
(iii) x3 - 2x2y + 3xy2 - 6y3
(iv) a(a + b - c) – bc

Answer :

(i) 6ab - b2 + 12ac - 2bc
   = (6ab - b2) + (12ac - 2bc)
   = b(6a - b) + 2c(6a - b)
   = (6a - b) (b + 2c)
(ii) x2 + y - xy - x
   = x2 - xy - x + y
   = x(x - y) - (x - y)
   = (x - y) (x - 1)
(iii) x3 - 2x2y + 3xy2 - 6y3
    = (x3 - 2x2y) + (3xy2 - 6y3)
    = x2(x - 2y) + 3y2(x - 2y)
    = (x - 2y) (x2 + 3y2)
(iv) a(a + b - c) - bc
    = a2 + ab - ac - bc
    = a(a + b) - c(a + b)
    = (a + b) (a - c)

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