Answer :

∫cosec2x(cos2x-sin2x)2dx

Opening the square





On multiplying (1-sin2x)(1-sin2x) equation reduces to


=∫(cosec2x-2+sin2x-2cos2x+ sin2x)dx


=∫(cosec2x-2+2sin2x-2cos2x)dx


=∫(-2(cos2x-sin2x)+cosec2x-2)dx


=∫(-2cos2x+cosec2x-2)dx


On solving this we get our answer i.e



=-sin2x-cotx-2x+c


Rate this question :

How useful is this solution?
We strive to provide quality solutions. Please rate us to serve you better.
Try our Mini CourseMaster Important Topics in 7 DaysLearn from IITians, NITians, Doctors & Academic Experts
Dedicated counsellor for each student
24X7 Doubt Resolution
Daily Report Card
Detailed Performance Evaluation
caricature
view all courses
RELATED QUESTIONS :

<span lang="EN-USRD Sharma - Volume 2

Evaluate the follRD Sharma - Volume 2

Evaluate the follRD Sharma - Volume 2

Evaluate the follRD Sharma - Volume 2

Evaluate the follRD Sharma - Volume 2

Evaluate the follRD Sharma - Volume 2

Evaluate the follRD Sharma - Volume 2

Evaluate the follRD Sharma - Volume 2

Evaluate the follRD Sharma - Volume 2