# A cone of radius 10 cm is divided into two parts by drawing a plane through the midpoint of its axis, parallel to its base. Compare the volume of the two parts.

Volume of a cone: volume of frustum = 1:7

Given: The figure is shown below

Explanation:

Radius of cone, r = 10cm

From the figure, we can see that the cone is divided into two equal parts by the axis. So,

In

AQD = APC = 90°

So, ∆AQD~∆APC ( by AA-similarity)

Now, the volume of frustum =

Comparing the volume of the frustum and the cone

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