Answer :
We have,
f (x) = x2 – x – 6
= x2 – 3x + 2x – 6
= x (x – 3) + 2 (x – 3)
= (x – 3) (x + 2)
f (x) = 0
(x – 3) (x + 2) = 0
(x – 3) = 0 or (x + 2) = 0
x = 3 or x = -2
∴ The zeros of the given polynomial are 3 and -2.
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