# Write the value o

To Find: tan–1(√3 ) – cot–1(–√3 )

Formula Used: Range of principal value for tan-1 θ is  and range of principal value for cot-1 θ is (0, π).

Now,

and,

As the value for cot does not lie in range, we will use the following concept,

Therefore, principal value = π - θ

Therefore,

Thus,

Hence,

tan–1(√3 ) – cot–1(–√3 ) = -π/2

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