Equation of XOY plane is z=0.
Since the required plane should pass through the point (2, - 3, 5).
We know, the vector equation of a plane perpendicular to a given direction and passing through a given point() is given by,
⟹ (z - 5)=0
hereis given byas it is perpendicular to XOY plane, and here
Hence, the desired equation for the plane is z=5.
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