# The product of a

Let the number be x.

Now, According to the question

(x)(x + 2) = 168

= x2 + 2x = 168

= x2 + 2x – 168 = 0

It’s a second degree equation.

and we can use splitting the middle term method.

= x2 + 14x – 12x – 168 = 0

= x(x + 14) – 12(x + 14) = 0

= (x–12) (x + 14)

There could be two values of x which are 12 and –14.

and the two number in each case would be (12,14) and (–14,–12).

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