Q. 14.0( 4 Votes )

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Answer :

Primarily, excluding the 3 things which are to be included, we have to select (r - 3) things from (n - 3), this can be done in n – 3Cr – 3 ways.


Now, the 3 particular things can be selected from 3 remaining things only in 1 way.


And the selected r things can be arranged in r! ways.


So, the number of permutations of n different things taking r at a time when 3 particular things are to be included is = r! n – 3Cr – 3

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