Q. 14.1( 85 Votes )

# Show that is 4√2

Let us assume that 4√2 is a rational number

where, b≠0 and a, b are integers

a, b are integers 4b is also integer

is rational which cannot be possible

which is an irrational number

it is contradicting our assumption

the assumption was wrong

Hence, 4√2 is an irrational number

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