Answer :

Let us assume that 4√2 is a rational number

where, b≠0 and a, b are integers

∵ a, b are integers ∴ 4b is also integer

is rational which cannot be possible

∵ which is an irrational number

∵ it is contradicting our assumption

∴ the assumption was wrong

Hence, 4√2 is an irrational number

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