Q. 14.3( 22 Votes )
Pritam drew a qua
A. Draw the given quadrilateral ABCD.
B. Draw the diagonal DB of quadrilateral ABCD.
C. Draw a parallel line through point A to diagonal DB of quadrilateral ABCD which intersects at F produced BC.
D. Join FD, AF||BD
ΔDFC is the required triangle.
∆ABD = ∆BFD (on same base DB and between same parallels DB and AF)
∴ ∆ABD = ∆BFD
∆DBC + ∆ABD = ∆BFD + ∆DBC (adding area of ∆DBC on both sides)
∴ quadrilateral ABCD = ∆DFC
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Pritam drew a quaWest Bengal Mathematics