Q. 15.0( 3 Votes )

# Mark the correct alternative in each of the following:Let A = {x ϵ R : –1 ≤ x ≤ 1} = B and C = {x ϵ R : X ≥ 0} and let S = {(x, y) ϵ A × B : x2 + y2 = 1} and S0 = {(x, y) ϵ A × C : x2 + y2 = 1} ThenA. S defines a function from A to BB. S0 defines a function from A to CC. S0 defines a function from A to BD. S defines a function from A to C

Given that

A = {x ϵ R: –1 ≤ x ≤ 1} = B

C = {x ϵ R: X ≥ 0}

S = {(x, y) ϵ A × B: x2 + y2 = 1}

S0 = {(x, y) ϵ A × C: x2 + y2 = 1}

x2 + y2 = 1

y2 =1 - x2

y ϵ B

Hence, S defines a function from A to B.

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