Q. 13.8( 26 Votes )

Length, breadth,

Answer :

Given: A cuboid shape box of medicine having,

Length (l) = 20 cm


Breadth (b) = 12 cm


Height (h) = 10 cm


To find: Surface Area of vertical faces (SA) = ?


Total Surface Area of the box (cuboid) (TSA) = ?


To find Surface Area of vertical faces of cuboid:


It will be found by adding vertical sides of cuboid, i.e., front side, back side, left side and right side of the cuboid.


So, Surface Area of vertical faces = (Area of front face) + (Area of back face) + (Area of left face) + (Area of right face)


SA = lh + lh + bh + bh


SA = 2 lh + 2 bh


SA = 2(l + b)×h


SA = 2(20 + 12)×10


SA = 2 × 32 × 10


SA = 640


Thus, Surface Area of vertical faces of the box is 640 cm2.


To find Total Surface Area of the box:


We have a formula for Total Surface Area of cuboid given by,


TSA = 2(lb + bh + hl)


TSA = 2(20×12 + 12×10 + 10×20)


TSA = 2(240 + 120 + 200)


TSA = 2(560)


TSA = 1120


Thus, Total Surface Area of the box is 1120 cm2.


Hence, Surface Area of vertical faces of the box is 640 cm2 and Total Surface Area of the box is 1120 cm2.

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