Q. 14.6( 14 Votes )

In Fig.1, PQ and

Answer :

Given, PQ and PR are two tangents to a circle with centre O and QPR = 46°.

Since, the radius drawn to these tangents will be perpendicular to the tangents,


OQ PQ and OR PR.


OQP = ORP = 90°


We know that the sum of angles in a quadrilateral is 360°.


OQP + QPR + ORP + QOR = 360°


90° + 46° + 90° + QOR = 360°


226° + QOR = 360°


QOR = 360° - 226°


QOR = 134°


Ans. QOR = 134°


Rate this question :

How useful is this solution?
We strive to provide quality solutions. Please rate us to serve you better.
Try our Mini CourseMaster Important Topics in 7 DaysLearn from IITians, NITians, Doctors & Academic Experts
Dedicated counsellor for each student
24X7 Doubt Resolution
Daily Report Card
Detailed Performance Evaluation
caricature
view all courses