# In a circle, a ch

O is centre of the circle.

DE is the chord 1 cm away from centre. CH is perpendicular on DE.

CH = 1 cm and DE = 6 cm

FG is the chord 2 cm away from centre. CI is perpendicular on FG.

CI = 2 cm

From centre C, CE and CG are joined.

CE and CG both are radius of the circle.

In ΔCHE we have,

CHE = 90° [CH is perpendicular on DE]

CH = 1 cm

HE = DE/2 = 3 cm [perpendicular drawn from centre bisects chord]

In ΔCGI we have,

CIG = 90° [CI is perpendicular on FG]

CI = 2 cm

CG = CE = √10 cm

FG = 2 × IG = 2√6 cm [perpendicular drawn from centre bisects chord]

The length of the chord is = 2√6 cm

Rate this question :

How useful is this solution?
We strive to provide quality solutions. Please rate us to serve you better.
Try our Mini CourseMaster Important Topics in 7 DaysLearn from IITians, NITians, Doctors & Academic Experts
Dedicated counsellor for each student
24X7 Doubt Resolution
Daily Report Card
Detailed Performance Evaluation
view all courses
RELATED QUESTIONS :

In a circle, two Kerala Board Mathematics Part-1

The bottom side oKerala Board Mathematics Part-1

In a circle of raKerala Board Mathematics Part-1

In a circle, a chKerala Board Mathematics Part-1