Q. 14.3( 3 Votes )

In a circle, a ch

Answer :


O is centre of the circle.


DE is the chord 1 cm away from centre. CH is perpendicular on DE.


CH = 1 cm and DE = 6 cm


FG is the chord 2 cm away from centre. CI is perpendicular on FG.


CI = 2 cm


From centre C, CE and CG are joined.


CE and CG both are radius of the circle.


In ΔCHE we have,


CHE = 90° [CH is perpendicular on DE]


CH = 1 cm


HE = DE/2 = 3 cm [perpendicular drawn from centre bisects chord]



In ΔCGI we have,


CIG = 90° [CI is perpendicular on FG]


CI = 2 cm


CG = CE = √10 cm



FG = 2 × IG = 2√6 cm [perpendicular drawn from centre bisects chord]


The length of the chord is = 2√6 cm


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