If the length of A. 15 cm

B. 16 cm

C. 17 cm

D. 34 cm

Let AB be the chord of length 16cm.

Given that,

Distance from centre to the chord AB is OC = 15 cm

Now,

OC ⊥ AB

Therefore,

AC = CB (Since perpendicular drawn from centre of the circle bisects the chord)

Therefore,

AC = CB = 8 cm

In right ΔOCA,

OA² = AC² + OC²

= 8² + 15²

= 225 + 64

= 289

OA = 17 cm

Thus, the radius of the circle is 17 cm