Answer :

Given: Fifth term of GP is 2


Let the first term be a and the common ratio be r.


According to the question,


T5 = 2


We know,


an = arn-1


a5 = a.r5-1


2 = ar4


GP = a,ar,ar2,…,ar8


Product required = a×ar×ar2×…×ar8


= a9.r36


= (ar4)9


= (2)9


= 512


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