If diameter of a road roller is 0.9 m and its length is 1.4 m, how much area of a field will be pressed in its 500 rotations?

We have the road roller which is cylindrical,

Now, given that

Length of the road roller, i.e., height of the cylinder (h) = 1.4 m

Diameter of the road roller = 0.9 m

Now, since the road roller is rotating, we can deduce that only the curved surface of the cylindrical road roller will be pressed against the field.

Area of the field pressed in 1 rotation = Curved surface area of the cylindrical road roller

Then, Area of the field pressed in 500 rotations = 500 (Curved surface area of cylindrical road roller) …(i)

So, curved surface area of cylinder is given by

CSA = 2πrh

Substituting values, we get

CSA =

CSA = 3.96

Now, using equation (i) we get

Area of the field pressed in 500 rotations = 500 × 3.96 = 1980 m2

Thus, area of field pressed by the road roller in 500 rotations is 1980 m2.

Rate this question :

How useful is this solution?
We strive to provide quality solutions. Please rate us to serve you better.
Related Videos
Surface Area of Right Circular Cylinder52 mins
Surface Area of Right Circular Cylinder49 mins
Surface Area of Cube and Cuboid49 mins
Surface Area and Volume of Spheres40 mins
Surface Area and Volume of Cone24 mins
Quiz | Mensuration42 mins
10 Important Questions of Surface Area and Volume51 mins
Surface Area and Volume of Right Circular Cylinders42 mins
Surface Area and Volume of Right Circular Cone37 mins
Quiz | Surface Area & Volumes49 mins
Try our Mini CourseMaster Important Topics in 7 DaysLearn from IITians, NITians, Doctors & Academic Experts
Dedicated counsellor for each student
24X7 Doubt Resolution
Daily Report Card
Detailed Performance Evaluation
view all courses