Q. 13.7( 21 Votes )

# I have written the number of children belonging to each of 40 families in our locality below—

I prepare a frequency distribution table of the above given data whose classes are 0 –2, 2–4, ……. etc.

From this frequency distribution table, let me understand and write

(i) class - interval

(ii) class - size

(iii) frequency of the class

(iv) class - limit.

Answer :

class - size = upper class boundary – lower class boundary

lower class boundary = lower limit - 0.5

Upper class boundary = upper limit + 0.5

Mid value of class

Frequency density

From the given data, we can see that number of children in the range 0 - 2 belongs to 11 families, Similarly for other ranges Table is formulated below, Using the above formulas.

Rate this question :

In a continuous frequency distribution table if the mid - point of a class is m and the upper class - boundary is u, then let us find out the lower class - boundary.

West Bengal MathematicsThe range of the data 12, 25, 15, 18, 17, 20, 22, 26, 6, 16, 11, 8, 19, 10, 30, 20, 32 is

West Bengal MathematicsLet us write the frequency density of the first class of the above frequency distribution table.

West Bengal MathematicsIn a continuous frequency distribution table, if the mid - point of a class is 42 and class size is 10, then let us write the upper and lower limit of the class.

West Bengal MathematicsLet us write the frequency density of the last class of the question (c).

West Bengal MathematicsIn a frequency distribution table, the midpoints of the classes are 15, 20, 25 30, ….. respectively. The class having midpoint as 20 is

West Bengal MathematicsThe class size of the classes 1–5, 6–10 is

West Bengal Mathematics