Q. 13.9( 56 Votes )

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Answer :

Untitled42.jpg


In the above figure, let AB be the tower and P and D be the positions of the two cars at an instant, observed from A. join A and E. The angles of depression are DAE and PAE. Given that, PD = 100 m. Since AE is parallel to BD, so, ADB = DAE = 45° and APB = PAE = 60°. Join P,D and A,B. We get two right-angled triangles ∆ABD and ∆ABP. We are to find AB. We use trigonometric ratio tan for both the triangles, using AB as height and BP as base for ∆ABP and AB as height and BD as base for ∆ABD.


From ∆ABD,



or, AB = BD


From ∆APB,



or, BD = BP√3


or, BP + 100 = BP√3


or, BP(√3-1) = 100


or,



Hence, the height of the tower is, AB = BD = BP + 100 = 136.61 + 100 = 236.61m

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