Q. 1


From a point 20

Answer :


https://gs-post-images.grdp.co/user_files/63094/15047/images/extra-9_files/ima1.gif

Given:

Distance of the point from the foot of the tower, d = 20m

Angle of elevation, θ = 30°

To find: Height of the tower, AB


Let AB be the height of the tower and C be the point.


In right angled Δ ABC,

tan [θ] = Opposite / Adjacent

Here θ = 30°

And also the opposite side is AB and the adjacent side is BC

tan 30 o = AB/BC


AB = BC tan 30°


From the question we know that BC = d = 20m


= 20 × (1 /√ 3) m

= 20 × 0.57735

= 11.56 m


Therefore the height of the tower is 11.56 m.

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