Q. 14.0( 5 Votes )
Find the longest pole length that can be put in a room of 10 m x 10 m x 5 m dimensions.
From the figure, FD is the longest pole that can be put in the cuboid.
Given: l = 10 m
b = 10 m
h = 5 m
First in right-angled triangle CBF, applying the Pythagoras theorem we get,
CF = 10√2 m
Now, we have to calculate FD, so applying the Pythagoras theorem in right-angled triangle DCF, we get,
DF2 = 225
DF = √225
DF = 15 m
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