# Find the longest pole length that can be put in a room of 10 m x 10 m x 5 m dimensions. From the figure, FD is the longest pole that can be put in the cuboid.
Given: l = 10 m
b = 10 m
h = 5 m

First in right-angled triangle CBF, applying the Pythagoras theorem we get, CF = 10√2 m

Now, we have to calculate FD, so applying the Pythagoras theorem in right-angled triangle DCF, we get, DF2 = 225
DF = √225
DF = 15 m

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