Q. 14.0( 5 Votes )

# Find the longest pole length that can be put in a room of 10 m x 10 m x 5 m dimensions.

Answer :

From the figure, FD is the longest pole that can be put in the cuboid.
Given: l = 10 m
b = 10 m
h = 5 m

First in right-angled triangle CBF, applying the Pythagoras theorem we get,

CF = 10√2 m

Now, we have to calculate FD, so applying the Pythagoras theorem in right-angled triangle DCF, we get,

DF2 = 225
DF = √225
DF = 15 m

Rate this question :

How useful is this solution?
We strive to provide quality solutions. Please rate us to serve you better.
Related Videos
Surface Area and Volume of Right Circular Cylinders42 mins
Surface Area and Volume of Spheres40 mins
Surface Area and Volume of Right Circular Cone37 mins
Quiz | Surface Area & Volumes49 mins
RD Sharma | Surface areas and volumes of Cube & Cuboid33 mins
Surface Area of Right Circular Cylinder52 mins
Surface Area of Right Circular Cylinder49 mins
Surface Area of Cube and Cuboid49 mins
Matter and Its Classification34 mins
Speed and Velocity59 mins
Try our Mini CourseMaster Important Topics in 7 DaysLearn from IITians, NITians, Doctors & Academic Experts
Dedicated counsellor for each student
24X7 Doubt Resolution
Daily Report Card
Detailed Performance Evaluation
view all courses