Answer :

Let,

Then,

cosθ =cos(90+37 )

Therefore, θ = (90+37)°

= 2sinθ.cosθ

= 2 sin(90+ 37).cos(90+ 37)

as cos(90 +θ)= – cos(θ) Because θ lies in second quadrant

= – 2 sin(37).cos(37)

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