Q. 14.0( 5 Votes )

# <span lang="EN-US

Answer :

Given area of the square = 4. cm^{2}

We know that area of the square = × d^{2}

d is the diagonal of the square

× d^{2} = 4.

d^{2} = 9

d = 3 cm

diagonal of the square = 3 cm

step – 1:

Draw the a horizonal line with the starting point as A and draw 45^{o} ray from point A.

(It is a square so, the angle between side and diagonal will be 90^{o})

Step – 2:

We know the length of diagonal, so cut the ray with 3 cm arc

Step – 3:

Connect the intersecting point with horizontal line and name the intersection point as O

The above fig. forms a right-angle triangle

Sin 45^{o} =

BO =

In square all sides are equal we can draw rest of the fig. with the same measurement.

Thus, a square can be drawn when its area is given.

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<span lang="EN-USKerala Board Mathematics Part II

<span lang="EN-USKerala Board Mathematics Part II

<span lang="EN-USKerala Board Mathematics Part II

<span lang="EN-USKerala Board Mathematics Part II

<span lang="EN-USKerala Board Mathematics Part II

<span lang="EN-USKerala Board Mathematics Part II