# Draw a square of area square centimetres.

Given area of the square = 4. cm2

We know that area of the square = × d2

d is the diagonal of the square × d2 = 4. d2 = 9

d = 3 cm

diagonal of the square = 3 cm

step – 1:

Draw the a horizonal line with the starting point as A and draw 45o ray from point A.

(It is a square so, the angle between side and diagonal will be 90o) Step – 2:

We know the length of diagonal, so cut the ray with 3 cm arc Step – 3:

Connect the intersecting point with horizontal line and name the intersection point as O The above fig. forms a right-angle triangle

Sin 45o =  BO = In square all sides are equal we can draw rest of the fig. with the same measurement. Thus, a square can be drawn when its area is given.

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