Q. 13.8( 19 Votes )
Construct ΔXYZ, such that XY+XZ= 10.3cm, YZ=4.9cm, ∠XYZ = 45°
Given: base YZ= 6cm, XY+XZ= 9cm and ∠Y = 50°
Required: To construct a ΔXYZ
Steps of construction:
i: Draw a segment YZ of length of 4.9cm.
ii: At vertex Y, construct ∠Y = 45° and produce a ray YA.
iii: Mark an arc on ray YA cutting at D such that YD = 9cm.
iv: Draw segment ZD.
v: Construct the perpendicular bisector of segment ZD.
vi: Name the point of intersection of ray YD and the perpendicular bisector of ZD as X.
vii: Draw segment XZ.
ΔXYZ is the required triangle.
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