Answer :

Given: base QR= 4.2cm, PQ+PR= 8.5cm and

Q = 40° of Δ PQR.


Required: To construct a ΔPQR


Steps of construction:


s


i: Draw a segment QR of length of 4.2cm.



ii: At vertex Q, construct Q = 40° and produce a ray QB.



iii: Mark an arc on ray QB cutting at D such that QD = 8.5cm.



iv: Draw segment DR.



v: Construct the perpendicular bisector of segment DR.



vi: Name the point of intersection of ray QB and the perpendicular bisector of DR as P.



vii: Draw segment RP.



ΔPQR is the required triangle.


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