Q. 14.2( 57 Votes )
Construct Δ PQR, in which QR= 4.2cm, ∠Q = 40° and PQ+PR= 8.5cm
Given: base QR= 4.2cm, PQ+PR= 8.5cm and
∠Q = 40° of Δ PQR.
Required: To construct a ΔPQR
Steps of construction:
i: Draw a segment QR of length of 4.2cm.
ii: At vertex Q, construct ∠Q = 40° and produce a ray QB.
iii: Mark an arc on ray QB cutting at D such that QD = 8.5cm.
iv: Draw segment DR.
v: Construct the perpendicular bisector of segment DR.
vi: Name the point of intersection of ray QB and the perpendicular bisector of DR as P.
vii: Draw segment RP.
ΔPQR is the required triangle.
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