Construct Δ PQR, in which ∠Q =70°, ∠R = 80° and PQ+QR+PR=9.5cm

Given: Q =70°,

R = 80° and

perimeter of Δ PQR

Steps of construction:

i: Draw a line segment XY of 9.5cm.

ii: From point X draw a ray XD at 70° and from Y draw a ray YE at 80°.

iii: Draw an angle bisector of X and Y, two angle bisectors intersect each other at point A.

iv: Draw a line bisector of XA and AY respectively these two-line bisectors intersect at point B and C.

v: Join AB and AC.

vi: Δ ABC is required triangle.

Rate this question :

How useful is this solution?
We strive to provide quality solutions. Please rate us to serve you better.
Related Videos
Champ Quiz | Mastering Triangles44 mins
RD Sharma | Important Proofs in Triangles28 mins
Triangles - Important Questions39 mins
Quiz | Are You Master of Triangles?48 mins
Champ Quiz | Congruency of TrianglesFREE Class
NCERT | Congruency of Triangles43 mins
NCERT | Triangle Inequalities47 mins
NCERT | Practice Imp. Qs. on Triangles44 mins
R.D. Sharma | Triangles33 mins
Champ Quiz | Know About Triangles50 mins
Try our Mini CourseMaster Important Topics in 7 DaysLearn from IITians, NITians, Doctors & Academic Experts
Dedicated counsellor for each student
24X7 Doubt Resolution
Daily Report Card
Detailed Performance Evaluation
view all courses