Answer :


Height of observer (say ED) = 1.5 m

Height of tower (say AC) = 30 m

Distance between observer and tower (say CD) = 28.5 m

Angle of elevation (AEB) = Ɵ (say)


Perpendicular distance between top of tower and eye of observer AB = AC – CB

AB = 30 m – 1.5 m

AB = 28.5 m


BE = CD = 28.5 m


tan θ = 1

θ = 45°

Hence, Angle of elevation = 45°

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