Answer :

Given:

Height of observer (say ED) = 1.5 m


Height of tower (say AC) = 30 m


Distance between observer and tower (say CD) = 28.5 m


Angle of elevation (AEB) = Ɵ (say)



Clearly,


Perpendicular distance between top of tower and eye of observer AB = AC – CB


AB = 30 m – 1.5 m


AB = 28.5 m


And,


BE = CD = 28.5 m


Now,





tan θ = 1


θ = 45°


Hence, Angle of elevation = 45°


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